C++ Code Review: calculates sum of series of type 1+1/2^2+1/3^3+...+1/n^n

Description: This program calculates sum of series of type 1+1/2^2+1/3^3+...+1/n^n.

Code:

//Compiling Tool: Code::Block IDE with MinGW

//Program calculates sum of series of type 1+1/2^2+1/3^3+...+1/n^n.

 

#include<iostream>

#include<conio.h> //for getch()

#include<math.h> // for pow()

 

using namespace std;

 

int main()

{

 

    double sum=0,a;

    int n,i;

 

    cout<<"Series Type:1+1/2^2+1/3^3+...+1/n^n"<<endl;

    cout<<"Enter the value of n:";

    cin>>n;

 

    for(i=1; i<=n; ++i)

    {

        a=1/pow(i,i);

        sum+=a;

    }

 

    cout<<"Sum="<<sum;

    getch();

}   

 

Output:

 

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