This C code shows how to find type of triangle by its input values. And code is helpful while user is in between any algorithm-like manipulation task.
code:
//Tested OK on Code::Blocks IDE 17.12 & Cygwin+GCC tools.
//Program to find the type of the triangle made by i/p values of
//its coordinates of its vertices.
#include <stdio.h>
//#include <conio.h>
#include <math.h>
#include<stdlib.h>
void main()
{
float x1,y1,x2,y2,x3,y3;
float a,b,c,m1,m2,m3;
// clrscr();
printf("\nEnter coordinates of vertex A(x & y respectively):- ");
scanf("%f%f",&x1,&y1);
printf("\nEnter coordinates of vertex B(x & y respectively):- ");
scanf("%f%f",&x2,&y2);
printf("\nEnter coordinates of vertex C(x & y respectively):- ");
scanf("%f%f",&x3,&y3);
if ((x1==x2 && x2==x3)||(y1==y2 && y2==y3))
{
printf("\nThese coordinates can't represent a triangle.");
printf("\nA,B & C are colinear & thus constitute a line.");
printf("\nHAVE A NICE DAY! BYE.");
getchar();
exit(0);
}
else
{
m1=(y2-y1)/(x2-x1);
m2=(y3-y2)/(x3-x2);
m3=(y3-y1)/(x3-x1);
}
if (m1==m2||m2==m3||m3==m1)
{
printf("\nThese coordinates can't represent a triangle.");
printf("\nA,B & C are colinear & thus consitute a line.");
printf("\nHAVE A NICE DAY! BYE.");
getchar();
exit(0);
}
a = sqrt(pow((x2-x3),2) + pow((y2-y3),2));
b = sqrt(pow((x3-x1),2) + pow((y3-y1),2));
c = sqrt(pow((x2-x1),2) + pow((y2-y1),2));
printf("\nLength of side AB is = %f",c);
printf("\nLength of side BC is = %f",a);
printf("\nLength of side CA is = %f",b);
if (a==b==c)
printf("\nTriangle made by these vertices is an equilateral triangle.\n");
else if (a==b||b==c||c==a)
{
if (a==b==c);
else
printf("\nTriangle made by these vertices is an isosceles triangle.\n");
}
else if (a!=b && b!=c && c!=a)
printf("\nTriangle made by these vertices is a scalene triangle.\n");
printf("\nHAVE A NICE DAY! BYE.\n");
getchar();
}
//end of program
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...till next post, bye-bye and take care.
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